-(-3x^2-3/5x-5)

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Solution for -(-3x^2-3/5x-5) equation: 


x in (-oo:+oo)

-(-3*x^2-((3/5)*x)-5) = 0

-((-3/5)*x-3*x^2-5) = 0

3*x^2+3/5*x+5 = 0

DELTA = (3/5)^2-(3*4*5)

DELTA = -1491/25

DELTA < 0

x belongs to the empty set

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